.003+3.7x=x^2

Solution for .003+3.7x=x^2 equation:

.003+3.7x=x^2

We move all terms to the left:

.003+3.7x-(x^2)=0

determiningTheFunctionDomain
-x^2+3.7x+.003=0

We add all the numbers together, and all the variables

-1x^2+3.7x+0.003=0

a = -1; b = 3.7; c = +0.003;
Δ = b2-4ac
Δ = 3.72-4·(-1)·0.003
Δ = 13.702
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.7)-\sqrt{13.702}}{2*-1}=\frac{-3.7-\sqrt{13.702}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.7)+\sqrt{13.702}}{2*-1}=\frac{-3.7+\sqrt{13.702}}{-2}
$